Answer:
The solution is (0, 3/4)
Step-by-step explanation:
Please copy and share the instructions. Here they are: Solve the following system of linear equations.
Both of the equations can be reduced (simplified):
2x+8y = 6 => x + 4y = 3
15x + 20y = 15 => 3x + 4y = 3
Let's use the elimination by addition and subtraction method. Multiply the first equation by -1, obtaining
-x - 4y = -3
Add the second 3x + 4y = 3
equation to the
first.
We get: 2x = 0.
Thus, x = 0. Substituting 0 for x in the 1st original equation yields:
2(0) + 8y = 6. Then y = 6/8, or y = 3/4.
The solution is (0, 3/4).
3y = 5x + 30
y + 5x = 50 .......(1)
3y - 5x = 30 .....(2) - rearranging the first equation.
Add (1) and (2):-
4y = 80
y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6
The 2 numbers are 6 and 20.
Answer:
173/1000
Step-by-step explanation:
B.
You are looking for something that does not let 25x go over 80.
Answer:
To find a complex conjugate, simply change the sign of the imaginary part (the part with the i). This means that it either goes from positive to negative or from negative to positive.
As a general rule, the complex conjugate of <span>a+bi</span> is <span>a−bi</span>.
Therefore, the complex conjugate of <span>3−2i</span> is <span>3+2i</span>.
Hope this helped!!... :D
Please correct me if I'm wrong!!.. :3
