Answer:
See below.
Step-by-step explanation:
Given :-
x² + bx + c = 0 if x₁ + x₂ = -b and x₁x₂ = c
Solving :-
a) x₁ = 1/2 and x₂ = -3/4
=> x² + -(1/2 + -3/4)x + 1/2(-3/4)
=> x² + -(-1/4)x + (-3/8)
=> x² + 1/4x - 3/8
=> 8x² + 2x - 3 = 0
b) x₁ = 1 + √5 and x₂ = 1 - √5
=> x² + -(1 + √5 + 1 - √5)x + (1 + √5)(1 - √5)
=> x² - 2x + 1 - 5
=> x² - 2x - 4 = 0
Answer:
distribute the 2 on the left side to become 2(x+7)-->2x+14=-4x+14, add 4x to both sides to become 2x+14+4x=-4x+14+4x-->6x+14=14, subtract 14 from both sides 6x+14-14=14-14-->6x=0 and divide both sides of the equation by 6 to get x alone, 6x/6=0/6-->x=0 so x would equal 0.
Step-by-step explanation:
N,R and T,U. Both are at 90 degree angles.
The least common multiple (LCM) of 5, 6, and 7 is 210.
5 × 42 = 210
6 × 35 = 210
7 × 30 = 210