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marusya05 [52]
2 years ago
10

Estimating for each pair of the number choose the number that is closet to 10.

Mathematics
1 answer:
luda_lava [24]2 years ago
6 0
10.9 is closer to 10.

If you add another 0 to the end of 10.9 to make it 10.90, you may realize that it is less than 10.99, which has a 9 in the hundredths place. 
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Which expression is NOT equivalent to −38⋅(−4+12)? Drag this expression to the box.
lesya [120]

I had this question so here's the answer and explanation! :)

Answer:

The answer to your question is the first option :D

Step-by-step explanation:

Original expression

                                -3/8 (-4 + 1/2)

First option    -3/8 (-4)  + (3/8)(1/2)       This option is not equivalent because

                                                             they forgot the negative sign of the

                                                             second term.

Second option (-3/8)(-4) + (-3/8)(1/2)    This option is equivalent to the

                                                              original. Distributive property

Third option    (-3/2)(-3 1/2)                 This option is equivalent to the original

Fourth option  (-3/8)(-3) + (-3/8)(-1/2)  This option is equivalent to the original

HOPE THIS HELPS :)

5 0
2 years ago
Read 2 more answers
suppose we toss 100 fair coins and record the percentage of heads. according to the central limit theorem, the percentages of he
SVETLANKA909090 [29]

answer is attached below

6 0
2 years ago
One number is 9 more than twice another. If their difference is 22, what is the larger number?
mafiozo [28]
Let, the numbers are: x, y
So, Equations will be: x - y = 22
x = 2y + 9

Substitute the value of x in first equation, 
2y + 9 - y = 22
y = 22 - 9
y = 13

x - 13 = 22
x = 22 + 13 = 35

In short, Larger number would be 35

Hope this helps!
4 0
3 years ago
Help please<br><br> 1 1/2% of what number is 10.05
MrRissso [65]

Answer:

10/25%

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
EleoNora [17]

Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

b) P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

c) P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

d) E(X) = 20*0.2= 4

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=20, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

Part b

We want this probability:

P(X=4)

And using the probability mass function we got:

P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

Part c

We want this probability:

P(X>3)

We can use the complement rule and we got:

P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

Part d

The expected value is given by:

E(X) = np

And replacing we got:

E(X) = 20*0.2= 4

3 0
3 years ago
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