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2 years ago

Find the value of x.

Mathematics

1 answer:

Ede4ka [16]2 years ago

5 0

Step-by-step explanation:

I would assume the answer would be a. 18 assuming your trying to find the entire value of a triangle but have a missing value

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A standard deck of cards has 52 cards, 4 of each type (Ace, King, Queen, Jack, 10,...,2). From a well-shuffled deck, you are dea

Wewaii [24]

Answer:

a)%85,5

b)%92,2

Step-by-step explanation:

a) To determine the probability of getting a hand with at least one face, we need to calculate the probability of the hand without any face firstly.

$(36/52)*(35/51)*(34/50)*(33/49)*(32/48)=0,145$

Then, we need to deduct this value from the probability 1

$1-0,145=0,855$

The probability of the hand with at least one face is %85,5.

b)To determine the probability of a hand with at least one ace and face we will track the same road again.

$(32/52)*(31/51)*(30/50)*(29/49)*(28/48)=0,0775$

Then, we need to deduct this value from the probability 1

$1-0,0775=0,922$

The probability of the hand with at least one ace and one face is %92,2.

3 0

2 years ago

Joshua's goal is to sell more than 20 items at a farmers' market. So far, he has sold 6 items. Each of his customers buys 2 item

amid [387]

Answer:

More than 7

Step-by-step explanation:

Given that:

Joshua's goal is to sell more than 20 items at a farmer's market.

Number of items already sold = 6

So, number of more items to be sold > Total number of items to be sold - Number of items already sold > 20 - 6 > 14

Given that each customer buys 2 items.

Let $c$ be the number of customers.

So, number of items bought be the customers = Number of items bought by each customer multiplied by the number of customers = $2c$

And as per the question statement,

Number of more items to be sold > 14 (as calculated in above step)

$2c>14\\\Rightarrow \bold{c>7}$

Therefore, the answer is: More than 7 additional customers are required.

3 0

2 years ago

Which statements about the hyperbola are true? Check all that apply. There is a vertex at (–5, 2). The center of the hyperbola i

skelet666 [1.2K]

Answer:

A, B, E,

Step-by-step explanation:

CAuse yes

4 0

2 years ago

Read 2 more answers

Joanna plans on hanging 3 pictures of different sizes on the wall of her staircase. She thinks it will look best if all 3 rectan

Natasha2012 [34]

In similar figures, the ratio between corresponding sides are the same.

$\frac{25}{35}=\frac{35}{49}$

Simplify the two to see that they are equal.
The top and bottom of the left fraction are divisible by 5.
The top and bottom of the right fraction are divisible by 7.

$\frac{5}7=\frac{5}7$

Of course, the dimensions of that third picture would have to be this fraction.
Let's test these answers.

$\frac{5}6\neq\frac{5}7$ ⇒ A is not a solution

$\frac{30}{42}=\frac{5}7$ ⇒ B is the solution
(divide the top and bottom by 6)

5 0

3 years ago

A partir del 1.° de diciembre, un camión de helados visita la calle de Sara cada 3 días y la calle de Ema cada 5 días. ¿Cuáles s

777dan777 [17]

Answer:

Los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

Step-by-step explanation:

Los múltiplos de un número son todos los posibles resultados de multiplicar ese número por todos y cada uno de los números naturales.

Es decir, los múltiplos de un número natural son los números naturales que resultan de multiplicar ese número por otros números naturales.

El conjunto de los múltiplos de un número determinado (salvo el cero) es infinito, pues existen infinitos naturales para multiplicar.

Para determinar cuáles son los primeros 2 días que el camión visita ambas calles el mismo día, debes encontrar los múltiplos de 3 y 5:

múltiplos de 3: 3; 6; 9; 12; 15; 18; 21; 24; 27; 30

múltiplos de 5: 5; 10; 15; 20; 25; 30; 35; 40; 45; 50

Podes observar que los 2 primeros números comunes o que coinciden entre los múltiplos de 3 y 5 son 15 y 30. Esto quiere decir que los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

7 0

2 years ago