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Stella [2.4K]
4 years ago
14

The probabilities of landing on 1, on 2, on 3, on 4, on 5 or on 6 when rolling a biased dice are shown in the table below.

Mathematics
1 answer:
ira [324]4 years ago
8 0

Answer:

99

Step-by-step explanation:

P(3) = 1-0.88 = 0.12

P(3 or 4) = 0.12 + 0.21 = 0.33

Expected no. = no

= 300(0.33) = 99

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