Answer: The zeros of the quadratic function are: 5/2+(1/2)*sqrt(31), 5/2-(1/2)*sqrt(31)
Step-by-step explanation:
Answer:
Step-by-step explanation:
the curve is representing the projectile. at t=0, the projectile is on the ground. at t=6, the projectile has finished its journey and is back on the ground. In between t=0 and t=6 will be the projectile's peak altitude. the point between t=0 and t=6 is t=3. So plug in t=3 and solve for s(t), and you get 36ft. gg
Answer:
783
Step-by-step explanation: