Lost as usual yep I am
2 answers:
Answer:
y = -3x -4
Step-by-step explanation:
A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.
The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.
The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...
3(x+3) +(y-5) = 0
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This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:
3x +9 +y -5 = 0 . . . . . eliminate parentheses
y = -3x -4 . . . . . subtract terms that are not "y"
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We have that
case 1)
<span>system of equations is
</span><span>y=−12x−1
y=14x−4
using a graph tool
see the attached figure
the solution of the system is the point (0.115,-2.385)
case 2)
</span>system of equations is
<span>blue line passing through coordinates A (0, -4) and B (4, -3)
</span><span>red line passing through coordinates C(0, -1) and D (4, -3)
</span>using a graph tool
see the attached figure
the solution of the system is the point (4,-3)<span>
</span>
case 1)
<span>system of equations is
</span><span>y=−12x−1
y=14x−4
using a graph tool
see the attached figure
the solution of the system is the point (0.115,-2.385)
case 2)
</span>system of equations is
<span>blue line passing through coordinates A (0, -4) and B (4, -3)
</span><span>red line passing through coordinates C(0, -1) and D (4, -3)
</span>using a graph tool
see the attached figure
the solution of the system is the point (4,-3)<span>
</span>
A) Add three <em>line</em> segments (AD, CF, BE) to the <em>regular</em> hexagon.
B) The area of each triangle of the <em>regular</em> hexagon is 35.1 in².
C) The area of the <em>regular</em> hexagon is 210.6 in².
<h3>How to calculate the area of a regular hexagon</h3>
In geometry, regular hexagons are formed by six <em>regular</em> triangles with a common vertex. We decompose the hexagon in six <em>equilateral</em> triangles by adding three <em>line</em> segments (AD, CF, BE).The area of each triangle is found by the following equation:
A = 0.5 · (9 in) · (7.8 in)
A = 35.1 in²
And the area of the <em>regular</em> polygon is six times the former result, that is, 210.6 square inches.
To learn more on polygons: brainly.com/question/17756657
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Brainly is erroneously preventing my response from being posted due to nonexistent profanity or links. So, I have converted my answer into an image file, which I have attached. I also attached an annotated diagram of the figure in the image you posted. Please let me know if you have trouble accessing either. Hope this helps.
