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vampirchik [111]
3 years ago
7

Lost as usual yep I am

Mathematics
2 answers:
denpristay [2]3 years ago
8 0

Answer:

  y = -3x -4

Step-by-step explanation:

A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.

The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.

The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...

  3(x+3) +(y-5) = 0

__

This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:

  3x +9 +y -5 = 0 . . . . . eliminate parentheses

  y = -3x -4 . . . . . subtract terms that are not "y"

Julli [10]3 years ago
5 0

Answer:

y=-3x-4

Step-by-step explanation:

If you are looking for a line that is perpendicular to the given line, you will need to:

1) Find slope of given line. You could do this by solving for y to put it into slope-intercept form, y=mx+b. m is the slope while b is the y-intercept.

2) Once you found slope of given line you can use it find the slope of line perpendicular to the given line. Perpendicular lines have opposite reciprocal slopes.

3) Then you can use point-slope form since you know a point (x1,y1) and you would have found the slope in 2).

Point-slope form is:

y-y1=m(x-x1)

where m is the slope and (x1,y1) is a point that you know is on the line.

4) The goal is y=mx+b form so you will need to get y by itself and distribute & simplify.

1)

7x-21y=39

Subtract 7x on both sides:

-21y=-7x+39

Divide both sides by -21:

y=(-7x)/(-21)+(39)/(-21)

Simplify fractions:

y=(x/3)-(13/7)

or

y=(1/3)x-(13/7)

The slope is 1/3.

2) The opposite reciprocal of 1/3 is -3/1=-3.

3)

y-5=-3(x--3)

y-5=-3(x+3)

4)

Add 5 on both sides:

y=-3(x+3)+5

Distribute-3 to terms inside the ( ):

y=-3x-9+5

Combine like terms:

y=-3x-4

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Step-by-step explanation:

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3 years ago
An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be
Sveta_85 [38]
Add the rest of the question
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3 years ago
Jane wishes to have 20,000 available at the end of 10 years so she deposit money into an account that pays 1.14% compounded mont
max2010maxim [7]

Answer:

\$17,846.12  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\ A=\$20,000\\ r=0.0114\\n=12  

substitute in the formula above  

\$20,000=P(1+\frac{0.0114}{12})^{12*10}  

P=\$20,000/[(1+\frac{0.0114}{12})^{120}]  

P=\$17,846.12  

5 0
4 years ago
What is the answer to 19+x/2=4?
salantis [7]
19+x/2=4
multiply 2 on both sides
19+x=4 times 2
19+x=8
subtract 19 on each side
x=8-19
subtract
x=-11
8 0
3 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
4 years ago
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