Equation #1:
|2x - 3| = 17
The first solution is
2x - 3 = 17
2x = 17 + 3 = 20
x = 10
The second solution is
3 - 2x = 17
-2x = 17 - 3 = 14
x = -7
The solutions are x = 10 or x = -7.
Equation #2:
|5x + 3| = 12
The only solution is
5x + 3 = 12
5x = 12 - 3 = 9
x = 9/5
Let us examine the given answers.
a. Equation #1 and #2 have the same number of solutions.
FALSE
b. Equation @1 has more solutions than Equation #2.
TRUE
c. Equation #1 has fewer solutions than equation #2.
FALSE
d. None of the statements a,b, or c apply.
FALSE
Answer: b.
Tables are created by substitute a set of input values into the function to create outputs. The required table is as shown below
<em>x | y</em>
<em>0 -3 </em>
<em>1 -2.5</em>
<em>2 -2 </em>
<h3>Tables and values</h3>
Tables are created by substitute a set of input values into the function to create outputs
Using x = 0, 1 and 2 as the input values
Given the function
y = 1/2x - 3
If x = 0
y = 1/2(0) - 3
y = -3
If x = 1
y = 1/2(1) - 3
y = -2.5
If x = 2
y = 1/2(2) - 3
y = -2
Hence the required table is as shown below
x | y
0 -3
1 -2.5
2 -2
Learn more on tables and values here: brainly.com/question/12151322
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Given:
10 yards required
5 2/3 yards on hand.
We need to subtract the yards on hand from the total yards required.
First, we need to convert the mixed fraction into an improper fraction.
5 2/3 = ((5*3)+2)/3 = (15+2)/3 = 17/3
Second, we need to multiply 10 by a fraction that will give us the denominator of 3.
10 * 3/3 = (10*3)/3 = 30/3
Third, we do subtraction using our derived fractions.
30/3 - 17/3 = (30-17)/3 = 13/3
Lastly, we simplify the improper fraction. Improper fraction is a fraction whose numerator is greater than its denominator. Its simplified form is a mixed fraction.
13/3 = 4 1/3
Arliss needs to buy 4 1/3 yards more to complete the required yard length.
Answer:
Area of walkway = 16(x+4) 
Step-by-step explanation:
Length of the sides of the square outdoor = x feet
Area of the square outdoor = length x length
= x * x
=

The square outdoor is surrounded by 4 feet of walkway. So that,
length of the walkway = (x + 2(4))
= (x + 8)
Area of walkway with outdoor = (x + 8)*(x + 8)
= (
+ 16x + 64) 
Area of walkway = Area of walkway with outdoor - Area of the square outdoor
= (
+ 16x + 64) - 
= 16x + 64
Area of walkway = 16(x+4) 