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lisov135 [29]
3 years ago
8

4 divided by 148 what is it

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0
4 divided by 148 is about 0.027

But 148 divided by 4 is 37
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The length and width of a rectangle have a sum of 90. What dimensions give the maximum area?
tekilochka [14]
w-width\\l-length\\\\2w+2l=90\\2l=90-2w\ \ \ \ /:2\\l=45-w\\\\A=wl\to A=w(45-w)=45w-w^2

Area\ of\ a\ rectangle\ is\ a\ square\ function.\\The\ maximum\ area\ is\ equal\ to\ the\ y-coordinate\ of\ vertex\\and\ "w"\ is\ equal\ to\ the\ x-coordinate\ of\ vertex.\\\\A(w)=45w-w^2\\\\a=-1;\ b=45;\ c=0\\\\x-coordinate\ of\ vertex:\frac{-b}{2a}\\\\w=\frac{-45}{2\cdot(-1)}=\frac{-45}{-2}=22.5\\\\l=45-22.5=22.5\\\\Solution:22.5\times22.5\ \ (This\ rectangle\ is\ a\ square).
4 0
4 years ago
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Factor completely 81x^4-16
mestny [16]
The will be (3x - 2) x (3x + 2) x (9x2 + 4)
7 0
3 years ago
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WILL MARK BRAINLIEST FOR BEST ANSWER! SERIOUS ANSWERS ONLY!
alexira [117]

Answer:

Step-by-step explanation:

2081.25 ; 2312.50 ; 2543.75 ; ..... 7500

a= 2081.25

d = 231.25

t_{n}= 7500

a + (n-1)d = t_{n}

2081.25 + (n-1) * 231.25 = 7500

(n -1) *231.25 = 7500 - 2081.25

231.25n - 231.25 = 5418.75

231.25n = 5418.75 + 231.25

231.25n = 5650

n = 5650/231.25  = 565000/23125

n = 904/37

n = 24 years 157 days

6 0
2 years ago
If r1 and r2 are the roots of the quadratic equation ax+bx+c=0 show that r1+r2=-b/and r1r2=c/a
velikii [3]
x_{1,2} =  \frac{-b+-  \sqrt{ b^{2} -4ac} }{2a}

is the formula for calculating x1 and x2

To prove x1 + x2 = -b/a all we need to do is to express x1 and x2 from equation above

once we do we will get -2b/2a which is equal to -b/a because square root part will negate each other. one has + sign in front and other - sign

Showing that x1x2 = c/a goes similar way.
the numerator parts is actually difference of squares. after that we will have:
-b^2 -b^2 + 4ac = 4ac

in denominator we have 2a*2a = 4a^2
4ac/4aa = c/a
4 0
3 years ago
Solve the inequality y/ -6 is greater than 10
pashok25 [27]
Y<-60 
hope this helps and good luck;)
4 0
4 years ago
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