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Murljashka [212]
3 years ago
9

Angle A= ? HELP HELP HELP

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

A = 41.41

Step-by-step explanation:

Since this is a right angle, we can use trig functions

cos A = adjacent/ hypotenuse

Cos A = 6/8

Taking the inverse cos of each side

cos ^ -1 ( cos A) = cos ^-1 ( 6/8)

A =41.40962211

Rounding to the nearest hundredth

A = 41.41

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Heyy could you help me out with this question I have been stuck in this question??​
Ludmilka [50]
I think the first box is perpendicular good luck
6 0
3 years ago
Which expressions show the expanded form for 200.06 choose all answers that are correct.
Anit [1.1K]

a. 2 x 100 0 x 1 0 x 1/10 6 1/100b. 2 x 100 0 x 1 0 x 1/100 6 1/1000

Hope it helps! :D

Btw, where is B?

4 0
3 years ago
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
Can someone answer for me please, if you're great at math.
jonny [76]
Assuming that c is the length of AB (as is usually the case in the angle-side notation for triangles):
If sin(35) = 12/c, we can transform by multiplying both sides by c, and dividing both by sin(35) to get
c = 12/sin(35)
Evaluating using a calculator gives 20.92 units.
3 0
3 years ago
Let FS R be a finite set. (a) Prove that F is closed (b) Prove that every point in F is an isolated point.
Lorico [155]

Answer:

a) Suppose that F is ordered in ascending order: F = \{x_1,\ldots, x_n\}. Then, the complement of F can be written as

F^c = (-\infty,x_1)\cup (x_1,x_2)\cup (x_2,x_3)\cup \cdots \cup (x_{n-1}, x_{n})\cup (x_n,+\infty)

which is the union of a finite number of open intervals, then F^c is an open set. Thus, F is a closed subset of the real numbers.

b) Take an arbitrary element of F, let us say x_k. Now, choose a real number \epsilon such that

0 there are not other element of F, because \epsilon is less that the minimum distance between x_k and its neighbors.

In case that k=1 we only consider 0, and if k=n we only consider 0.

Then, all points of F are isolated.

Step-by-step explanation:

8 0
3 years ago
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