The blue figure is translated <u>5</u> units <u>left</u> and <u>2</u> units <u>down</u> from the red figure.
Answer:
Option (2)
Step-by-step explanation:
On a graph, factors or zeros of a polynomial function f(x) are represented by the x-intercepts (values for y = 0).
From the graph attached,
Quadratic function has two x-intercepts, x = 1 and x = 6.
Therefore, (x - 1) and (x - 5) are the zero factors of the given polynomial.
Option (2) will be the answer.
The equation of the line is 2x + 5y = 11 hat passes through the points (3,1) and (-2,3)
<h3>What is a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
![\rm m =\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Crm%20m%20%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
We have two points:
(3,1) and (-2,3)
The equation of the line passing through the points (3,1) and (-2,3)
![\rm (y - 3) = \dfrac{3-1}{-2-3}(x+2)](https://tex.z-dn.net/?f=%5Crm%20%28y%20-%203%29%20%3D%20%5Cdfrac%7B3-1%7D%7B-2-3%7D%28x%2B2%29)
![\rm (y - 3) = -\dfrac{2}{5}(x+2)](https://tex.z-dn.net/?f=%5Crm%20%28y%20-%203%29%20%3D%20-%5Cdfrac%7B2%7D%7B5%7D%28x%2B2%29)
5y - 15 = -2x - 4
2x + 5y = 11
Thus, the equation of the line is 2x + 5y = 11 hat passes through the points (3,1) and (-2,3)
Learn more about the slope of the straight line here:
brainly.com/question/3493733
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Maggie, you must either share the graphs or forget about them and solve the entire problem yourself with your own graph.
12 < 3b reduces to 4<b, and 2b + 14<4 reduces to 2b < -10, or b < -5.
You have only one variable here (b), so your graph will be one-dimensional (a horizontal line which is the b-axis).
First place a circle (open circle) at b = -5, and then draw an arrow to the left from b = -5. Next, place a circle at b = 4, and then draw an arrow to the right from b = 4. Note that there will be no arrow between b=-5 and b=4.