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Elanso [62]
1 year ago
12

Which graph represents the equation x2 8y

Mathematics
1 answer:
LekaFEV [45]1 year ago
3 0

Therefore by making a line through following points we can make graph which is parabola in shape

<h3>What is equation ?</h3>

Two things are equal, according to an equation. Like this: 9 + 2 = 11 . It will have an equivalent sign "=". According to that equation, "this equals that" is expressed as "what is on the left (9 + 2) is equal to what is on the right (11).

Here,

Given Equation : x² = 8y

Given Equation agrees with conventional equation of parabola on positive y-axis

x² = 4ay

Comparison of the two equations yields,

4a = 8 ⇒ a = 2

Focus of parabola = ( 0 , 2 ) ( 0 , 2 )

Parabola vertex equals ( 0 , 0 )

Axis of Symmetry = y-axis

To sketch its, we find some points

with x = 4 or -4 we get

4² = 8y ⇒ 16 = 8y ⇒ y = 2

So, points are ( 4 , 2 ) and ( -4 , 2 ) ( -4 , 2 )

we obtain when x = 8 or -8.

(-8)² = 8y ⇒ 64 = 8y ⇒ y = 8

So, points are ( 8 , 8 ) and ( -8 , 8 ) ( -8 , 8 )

Therefore by making a line through following points we can make graph which is parabola in shape

To know more about equation , visit

brainly.com/question/10413253

#SPJ4

The correct question is :-

Which graph represents the equation x2 = 8y?

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The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b
ANEK [815]

Answer:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

4 0
4 years ago
100 points! Please help asap! Look at the picture attached. My teacher said that both 1 and 2 are neither can someone explain wh
Neko [114]

Answer:

Your teacher is right, there is not enough info

Step-by-step explanation:

<h3>Question 1</h3>

We can see that RS is divided by half

The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS

So P is not on the perpendicular bisector of RS

<h3>Question 2</h3>

We can see that PD⊥DE and PF⊥FE

There is no indication that PD = PF or ∠DEP ≅ FEP

So PE is not the angle bisector of ∠DEF

6 0
3 years ago
Chantel starts a savings account with $37. Each month she deposits $15 more into her account. Chantel now has saved $97. Which e
I am Lyosha [343]

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5 0
3 years ago
Daniel drew a toy from a treasure chest containing 30 different toys. He selected a bouncy ball without replacement and then sel
borishaifa [10]

Answer:

Pr = \frac{1}{870}

Step-by-step explanation:

Given

n =30

Required

Probability of selecting 2 toys of different types

From the question, we understand that all toys are different i.e. 1 of each type.

And the selection is without replacement;

So, after the first toy is selected; there are n - 1 toys left.

So, the probability is:

Pr = \frac{1}{n} * \frac{1}{n - 1}

Substitute n =30

Pr = \frac{1}{30} * \frac{1}{30- 1}

Pr = \frac{1}{30} * \frac{1}{29}

Pr = \frac{1}{30*29}

Pr = \frac{1}{870}

5 0
3 years ago
An athlete ran 10 times around the circular track shown below. Approximately how many meters did the athlete run?
Anon25 [30]

Answer:

Step-by-step explanation:

Since the picture isn't given. I have no idea what the radius or diameter is and as such, have no definite answer for you.

However, from the question, if he's to run round the circular track once, then he must have run a total of

2πr meters, with r being the radius.

Now, the question says that he ran round the track 10 times, this means that whatever value we get there, for 1 trial, we multiply it by 10, to get the value for 10 trials. Essentially,

10 * 2πr

The value gotten is the needed answer. All you have to do is substitute r for the value you have in your diagram. We already know that π is 3.142

5 0
3 years ago
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