Answer:
No. The amounts of change are the same, but the original amounts are different.
Answer:
-7/3 < -3/4 < 0.5 < 2/3 < 1.2
Step-by-step explanation: Heres your answer. Sorry if its wrong.
Answer:
x =196
Step-by-step explanation:
Answer:
The probability that the total weight of the passengers exceeds 4222 pounds is 0.0018
Step-by-step explanation:
The Central limit Theorem stays that for a large value of n (21 should be enough), the average distribution X has distribution approximately normal with mean equal to 182 and standard deviation equal to 30/√21 = 6.5465. Lets call W the standarization of X. W has distribution approximately N(0,1) and it is given by the formula

In order for the total weight to exceed 4222 pounds, the average distribution should exceed 4222/21 = 201.0476.
The cummulative distribution function of W will be denoted by
. The values of
can be found in the attached file.

Therefore, the probability that the total weight of the passengers exceeds 4222 pounds is 0.0018.