-1/6 Is the answer for this!!
Answer:
I think so.
Step-by-step explanation:
With letters, no, and some shapes would be reversed, like a triangle with lengths that are all different from eachother.
Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
Well, first off, to solve for this, we can write the expression and then solve from there.
Expression: 8x + 3 = 29
So, now that we have our expression, we can solve for our missing number using the balancing method.
8x + 3 = 29
8x + 3 - 3 = 29 - 3 (we subtracted the three because we needed to get rid of the three on the left side of the equation do now we are just left with 8x = 26.
8x = 26
8x/8 = 26/8. (So, the 8 on the left side cancels out and we are just left with X.
X = 26/8
X = 13/4
X = 3 and 1/4
So, in conclusion, the answer to this question is: X = 3 and 1/4 as a mixed number or 13/4 as an improper fraction.
Glad I could help!
The answer is C, one over thirty-two
