Question

I did try this problem out 5 times and I did put the -1 in for the x idk what I did wrong

Answer 1

g(x)=3x^2-2(x+7)/2x+5

g(-1)=3(-1)^2-2(-1)+7/2(-1)+5

Do the numerator first

(3)(-1)(-1)-2(-1)+7

3+2+7

=12

2(-1)+5

-2+5

=3

Numerator= 12 , Denominator=3

Numerator/ Denominator = 12/3=4

Answer: g(-1)=4

Answer 2

Answer:

$\large\boxed{g(-1)=4}$

Step-by-step explanation:

In this question. we would be plugging in -1 to all of the x variables.

The equation we are solving is:

$g(x)=\frac{3x^2-2x+7}{2x+5}$

You would plug in -1 to all of the x variables.

Your equation should look like this:

$g(x)=\frac{3(-1)^2-2(-1)+7}{2(-1)+5}$

Now, you solve:

$g(x)=\frac{3(-1)^2-2(-1)+7}{2(-1)+5}\\\\\text{Lets start with the top}\\\\g(x)=\frac{3(1)-2(-1)+7}{2(-1)+5}\\\\g(x)=\frac{3-2(-1)+7}{2(-1)+5}\\\\g(x)=\frac{3+2+7}{2(-1)+5}\\\\g(x)=\frac{12}{2(-1)+5}\\\\\text{We can do the bottom now}\\\\g(x)=\frac{12}{2(-1)+5}\\\\g(x)=\frac{12}{-2+5}\\\\g(x)=\frac{12}{3}\\\\\text{Divide the fraction}\\\\g(-1)=4$

When you're done solving, you should get 4.

This means that when g is -1, the answer would be 4.

g(-1) = 4

I hope this helped you out.

Good luck on your academics.

Have a fantastic day!