Answer:
F. 6s > 4s +8
Step-by-step explanation:
From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.
From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.
For Heskey's distance to exceed Ward's distance you want ...
6s > 4s +8 . . . . . . matches choice F
Answer: The student's estimate is off by 12%
Like terms
<span>D) Terms that have identical variable parts.</span>
An equation has the following parts:
1) Coefficient
2) Variable
3) Operator
4) Constants
4x + 3 = 11
4 is the coefficient
x is the variable
3 and 11 are the constants
4x - 3x + 8x ⇒ like terms ; they have identical variable parts, x.
Answer:
x = 10
Step-by-step explanation:
Form the information given, we can deduce that:
m<OPQ is an exterior angle of ∆NOP = (6x - 15)°
m<PNO = (2x + 18)° and m<NOP = (2x - 13)° are both interior angles that are opposite to the exterior angle.
Therefore, based on the exterior angle theorem:
m<OPQ = m<PNO + m<NOP
(6x - 15)° = (2x + 18)° + (2x - 13)°
Solve for x
6x - 15 = 2x + 18 + 2x - 13
6x - 15 = 4x + 5
6x - 15 - 4x = 4x + 5 - 4x (Subtraction property of equality)
2x - 15 = 5
2x - 15 + 15 = 5 + 15 (addition property of equality)
2x = 20
2x/2 = 20/2 (division property of equality)
x = 10
Answer:
Your answer is Jacob had $1.40 left
