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Elena-2011 [213]
4 years ago
11

How to become a software tester?

Computers and Technology
1 answer:
HACTEHA [7]4 years ago
5 0
You should look on google to see if there are any websites
You might be interested in
Refer to the method f:
Goshia [24]
<h2>This function will land up in infinite function call</h2>

Explanation:

first time when the function gets invoked,

f(6,8), so k=6 & n=8, inside the function it checks k==n, ie. 6==8, returns false, then one more if is available, so 6>8 is check for , once again it is false and else loop is executed, the function is called recursively using f(k-n,n), that is f(6-8,8), it means f(-2,8) is passed.

Second time,

if(-2==8) is false, so if(-2>8) is again false and function f(-10, 8) is called

if(-10==8) is false, so if(-10>8) is again false and function f(-18,8) is called

if(-18==8) is false, so if(-18>8) is again false and function f(-26,8) is called

So this goes recursively and ends in an infinite function call.

5 0
4 years ago
2- There are many different design parameters that are important to a cache’s overall performance. Below are listed parameters f
katen-ka-za [31]

Answer:

1. 2588672 bits

2. 4308992 bits

3. The larger the data size of the cache, the larger the area of ​​memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.

Explanation:

1. Number of bits in the first cache

Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))

total bits = 2^15 (1+14+(32*2^1)) = 2588672 bits

2. Number of bits in the Cache with 16 word blocks

Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))

total bits = 2^13(1 +13+(32*2^4)) = 4308992 bits

3. Caches are used to help achieve good performance with slow main memories. However, due to architectural limitations of cache, larger data size of cache are not as effective than the smaller data size. A larger cache will have a lower miss rate and a higher delay. The larger the data size of the cache, the larger the area of ​​memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.

5 0
3 years ago
Which girl is he baddest 1. Shawty 2.Lisa 3.Ashley
Ainat [17]

Answer:

. . . . . . . S H A W T Y.. . .. . .

3 0
3 years ago
How many calories should i eat a day calculator to lose weight.
Slav-nsk [51]
Limit yourself to 4000 a day , it helps.
8 0
2 years ago
HW4:
julsineya [31]

Answer:

Check the explanation

Explanation:

1)

import java.util.*;

public class ArrayStack {

// Declare an Array List

ArrayList<String> aList;

// Constructor that Instantiates arrayList object

ArrayStack() {

aList = new ArrayList<String>();

}

public void push(String object) {

//Add the Value

aList.add(object);

}

public String pop() {

String ret = null;

//Check the size of list if 0 means Stack is Empty

if (aList.isEmpty())

System.out.println("Stack is Empty");

else {

//Return the last value entered as Stack is LAST IN FIRST OUT

// Remove it

ret = aList.get(aList.size() - 1);

aList.remove(aList.size() - 1);

}

return ret;

}

public String peek() {

String ret = null;

//Check the size of list if 0 means Stack is Empty

if (aList.isEmpty())

System.out.println("Stack is Empty");

else {

//Return the last value entered as Stack is LAST IN FIRST OUT

// DO not remove it

ret = aList.get(aList.size() - 1);

}

return ret;

}

public boolean isEmpty() {

//Check the size of list if 0 means Stack is Empty

return aList.size()==0;

}

public static void insertionSort(int arr[], int n)

{

int i, j;

for(i=2;i< n;i++){

arr[0] = arr[i];

j = 1;

while(j <= i-1){

/* implement your code here /*

/* you must start compare arr[j] with a[0], notice that j = 1 */

}

}

}

public static void main(String[] args) {

// TODO Auto-generated method stub

ArrayStack aStack = new ArrayStack();

aStack.push("Hey");

aStack.push("Hello");

aStack.push("Bye");

System.out.println(aStack.pop());

System.out.println("Peek: " + aStack.peek());

System.out.println(aStack.pop());

System.out.println(aStack.isEmpty());

System.out.println(aStack.pop());

// int arr[] = new int[] {3,4,2,1,6,7,5};

// insertionSort(arr,7);

// System.out.println(Arrays.toString(arr));

}

}

LinkedQueue

interface QueueInterface {

public void enqueue(Object item);

// Effect: Adds item to the rear of this queue.

// Precondition: This queue is not full.

// Postcondition: item is at the rear of this queue.

public Object dequeue();

// Effect: Removes front element from this queue and returns it.

// Precondition: This queue is not empty.

// Postconditions: Front element has been removed from this queue.

// Return value = (the removed element)

public boolean isEmpty();

// Effect: Determines whether this queue is empty.

// Postcondition: Return value = (this queue is empty)

public boolean isFull();

// Effect: Determines whether this queue is full.

// Postcondition: Return value = (queue is full)

public int size();

}

public class LinkedQueue implements QueueInterface {

private class QueueNode

// Used to hold references to queue nodes for the linked queue

// implementation

{

private Object info;

private QueueNode link;

}

private QueueNode front; // reference to the front of this queue

private QueueNode rear; // reference to the rear of this queue

public LinkedQueue()

// Constructor

{

front = null;

rear = null;

}

public void enqueue(Object item)

// Adds item to the rear of this queue.

{

QueueNode newNode = new QueueNode();

newNode.info = item;

newNode.link = null;

if (rear == null)

front = newNode;

else

rear.link = newNode;

rear = newNode;

}

public Object dequeue()

// Removes front element from this queue and returns it.

{

Object item;

item = front.info;

front = front.link;

if (front == null)

rear = null;

return item;

}

public boolean isEmpty()

// Determines whether this queue is empty.

{

if (front == null)

return true;

else

return false;

}

public Object peek()

// Determines whether this queue is empty.

{

if (front == null)

return null;

else

return front.info;

}

public int size()

// Determines whether this queue is empty

{

QueueNode curr = front;

int count = 0;

while (curr != null) {

++count;

curr = curr.link;

}

return count;

}

public String toString()

// Determines whether this queue is empty.

{

QueueNode curr = front;

String res = "";

while (curr != null) {

res = res + curr.info + " ";

curr = curr.link;

Note that i could not complete the answers to all the question because the codes are above the brainly character limit, you might need to ask the question 2 and 3 separately.

Kindly check the outputs in the attached images below

5 0
4 years ago
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