Answer:
N = 35 × 34^6
N = 54,068,154,560
Step-by-step explanation:
Given;
The license plate have 7 characters.
Each character can be a capital letter, or a digit except for 0.
There are 26 capital letters
And there are 9 digits excluding 0
The total number of possible entries in each character is;
26+9 = 35
The number of license plates in which no two adjacent characters are the same are;
For no two adjacent characters of the license plate not to be the same that is no two characters that follow each other can be the same, the number of possible entries in the adjacent characters apart from the first character would be reduced by one.
N = 35 × 34 ×34×34×34×34×34
N = 35 × 34^6
N = 54,068,154,560
Therefore, there are 54,068,154,560 possible license plates
Answer:
TQ = 10
Step-by-step explanation:
The diagonal divides the square into 2 right triangles with the diagonal being the hypotenuse.
Using Pythagoras' identity in triangle TPQ
TQ² = PQ² + PT²
TQ² = 10² + 10² = 100 + 100 = 200 ( take square root of both sides )
TQ = = = × = 10
Question
Tom, Sam, and Matt are counting drum beats.
Tom hits a drum every 2 beats.
Sam hits a drum every 5 beats.
Matt hits a drum every 8 beats.
Tom, Sam, and Matt start hitting their drums at the same time.
How many beats is it before Tom, Sam, and Matt hit their drums at the same time?
— Need help ASAP, with the explanation to the answer if possible. —
(is this the Question )
Answer:
Step-by-step explanation:
Present age of Barry = b
Present age of sister = s
Barry is 8 years older than his sister means if we subtract 8 from present age of Barry both will be of equal age
s=b-8 ............(1)
In 3 years means we have to add 3 in their present age
s+3=b+3
then
he will be twice as old as
2(s+3)=(b+3
2s+6=b+3
2s=b+3-6
2s=b-3...............(2)
Put the value of s from (1) to (2), we have
2(b-8)=b-3
2b-16=b-3
2b-b=-3+16
b=13
Put the value of b in (1)
s=13-8
s=5
Present age of Barry = b = 13
Present age of sister = s = 5
Answer:
185
Step-by-step explanation:
sorry. had to do something but im bsck :)