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2 years ago

12

Solve for x.2/3(5x + 6) + 2 = 36

1 answer:

babymother [125]2 years ago

8 0

the Answer is x=9 enjoy

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Please help me !!!!!

Angelina_Jolie [31]

Answer:

slope means the monthly salary is $425

Step-by-step explanation:

4050 - 3200 / 6 - 4 = 850 / 2 which is same as 425 / 1

4475 - 4050 / 7 - 6 = 425 / 1

4900 - 4475 / 8 - 7 = 425 / 1

8 0

2 years ago

Curtis is packing to move. He finds 23 photo albums in the attic and 45 albums in a closet. If he divides them equally among 4 b

belka [17]

He will put 17 albums in each box

7 0

3 years ago

Read 2 more answers

Which equation is the inverse of y = 16x2 + 1?

Llana [10]

Answer:

$y=\frac{\sqrt{x-1} }{4}$

Step-by-step explanation:

The given equation is

$y=16x^2+1$

For this function to have an inverse, we must restrict the domain, say $x\ge0$

We interchange x and y to get,

$x=16y^2+1$

We now make y the subject to get;

$x-1=16y^2$

$x-1=16y^2$

We divide through by 16 to get;

$\frac{x-1}{16}=y^2$

We now take the square root of both sides to get;

$\pm \sqrt{\frac{x-1}{16}}=y$

$y=\pm \frac{\sqrt{x-1} }{4}$

Since $x\ge 0$ , the inverse function is

$y=\frac{\sqrt{x-1} }{4}$

6 0

3 years ago

Is 4/10 more, less or equal to half

zubka84 [21]

Answer:

less

Step-by-step explanation:

5/10 is equal to one half, but 4/10 is less than one half

7 0

2 years ago

Read 2 more answers

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago