Answer:
0
Step-by-step explanation:
Simplifying
-7(x + -2) + 1 = 15 + -7x
Reorder the terms:
-7(-2 + x) + 1 = 15 + -7x
(-2 * -7 + x * -7) + 1 = 15 + -7x
(14 + -7x) + 1 = 15 + -7x
Reorder the terms:
14 + 1 + -7x = 15 + -7x
Combine like terms: 14 + 1 = 15
15 + -7x = 15 + -7x
Add '-15' to each side of the equation.
15 + -15 + -7x = 15 + -15 + -7x
Combine like terms: 15 + -15 = 0
0 + -7x = 15 + -15 + -7x
-7x = 15 + -15 + -7x
Combine like terms: 15 + -15 = 0
-7x = 0 + -7x
-7x = -7x
Add '7x' to each side of the equation.
-7x + 7x = -7x + 7x
Combine like terms: -7x + 7x = 0
0 = -7x + 7x
Combine like terms: -7x + 7x = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.
Answer:
Step-by-step explanation:
To start of u have to subtract 150 with 180 which is 180 (cuz its a straight line and E to get angle S
Now that we know that 180-150= 30
We add S and R then subtract by 180
so 80+ 30= 110
then we said subtract 180
180-110= 70
Now we know that angle Q is 7-
Then the bottom is RS & SE (NOT REALLY SURE)
It is a Remote Interior Angle
IF RIGHT PLZ GIVE BRAINLIEST
THANK U
HAVE A GREAT DAY AND BE SAFE :)
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Answer:
a) Michiko needs to buy 18 tins of paint.
b) cost of paint would be $152.82
Step-by-step explanation:
Surface area of cuboid = 2lw + 2lh + 2hw
Length (l) = 2.4 m
Width (w) = 1.2 m
Height (h) = 0.6 m
SF = 2(2.4 × 1.2) + 2(2.4 × 0.6) + 2(0.6 × 1.2)
= 5.76 + 2.88 + 1.44
= 10.08 meter²
Paint coverage is 4.5 meter² per liter.
Total paint used in one coat =
= 2.24 liters
Paint used in double coats = 2.24 × 2 = 4.48 liters
a) Size of one tin paint = 250 ml
1 liters = 1000 ml
4.48 liters = 4.48 × 1000 = 4480 ml
Number of tins needed by Michiko =
= 17.92 ≈ 18 tins
b) Cost of one tin of metal paint = $8.49
∴ cost of 18 tins of paint = $152.82
a) Michiko needs to buy 18 tins of paint.
b) cost of paint would be $152.82
Since CB || ED and CB = ED,
by the alternate interior angles theorem,
mE = mC, and mD = mB.
with CB = ED, we can conclude that CBF = EDF, by SAS congruent theorem.
