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puteri [66]
3 years ago
6

There are eight lockers in a school hallway and five of them have star stickers on the inside. If the first locker opened does n

ot have a star in it, what is the probability that the second won’t either?
Mathematics
1 answer:
Gemiola [76]3 years ago
7 0
5/7. You are eliminating one of the 8 original lockers yet you still have 5 possible stars left. Hence a probability of 5 stars over 7 possible lockers left. 5/7 = .7143 or 71.43 %
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Solve for n and simplify: n/15=24/16
Andrew [12]

Answer:

n=45/2

or

n=22.5

or

22  1/2

Step-by-step explanation:

5 0
3 years ago
Consider the circle where QR = 7 units and UT= 4 units. What is the value of X, if x represents the length of segment ST? A. 15
julia-pushkina [17]

Option C:

x = 6  units

Solution:

QR = 7 units, RS = 5 units, UT = 4 units and ST = x

<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>

⇒ SR × SQ =  ST × SU

⇒ 5 × (5 + 7) =  x × (x + 4)

⇒ 5 × 12 =  x² + 4x

⇒ 60 =  x² + 4x

Subtract 60 from both sides.

⇒ 0 = x² + 4x - 60

Switch the sides.

⇒ x² + 4x - 60 = 0

Factor this expression, we get

(x - 6)(x + 10) = 0

x - 6 = 0, x + 10 = 0

x = 6, x = -10

Length cannot be in negative measures.

x = 6 units

Option C is the correct answer.

6 0
3 years ago
A learning sits a corne of a square with length 10 meters pictures
barxatty [35]
Wait What...? Sorry the question doesn't make any sense to me.
8 0
3 years ago
Find the value of y that makes each equation true for all values of x x+5+11x=12x+y
Readme [11.4K]
Ok, let's simplify the left side first by adding the x's together
We get:
12x+5=12x+y
So if we subtract 12x from each side, it cancels it out on both sides, leaving us with 5=y or y=5

If we plug that back into the original we simplified of 12x+5=12x+y, we would have: 12x+5=12x+5, which is true.  :D
5 0
4 years ago
A team of 5people to be selected from 7women &amp; 6men. Find the number of different teams that could be selected if there must
vova2212 [387]

Answer:

1246 teams

Step-by-step explanation:

We are told there are 7women & 6men.

If 5 people are selected and there must be more women than men in the team.

This means there must be a minimum of 3 women.

Thus;

For 3 women;

7C3 × 6C2 = 525

For 4 women;

7C4 × 6C3 = 700

For 5 women;

7C5 × 6C0 = 21

Thus;

Total = 525 + 700 + 21 = 1246 teams

8 0
3 years ago
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