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BabaBlast [244]

2 years ago

12

If 5 miles is 8 kilometers, which of the following is correct? A. 47.5 miles is 76 kilometers B. 52.5 miles is 86 kilometers C.

22.5 miles is 34 kilometers D. 12.5 miles is 22 kilometers

1 answer:

RUDIKE [14]2 years ago

4 0

Answer:

A.47.5 miles is 76

Step-by-step explanation:

in real life its like 76.44, but im rounding

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What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

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3 years ago

A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di

denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is $0.432\, \frac{m}{s^{2}}$

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , $V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}$

Now centripetal acceleration is given by

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3 years ago

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Katen [24]

Answer:

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Answer:

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