If 49% of a number is 56 what was the original numeber

Mathematics

2 answers:

Viktor [21]3 years ago

8 0

Answer:

1.42%

Step-by-step explanation:

let y be the unknown number

49% × y = 49y%

49y% = 56

then the co-efficient of 'y' that is 49% will cancel out leaving 'y' and resulting in 56÷49 resulting in 1.42

therefore the original number is 1.42

pashok25 [27]3 years ago

6 0

Answer:

142.85 (rounded off to two decimal places)

Step-by-step explanation:

given

(49/100)x = 56

x = (56/49)100

x = (8/7)(100)

we get

x= 142.85....

You might be interested in

I NEED A LOT OF HELP PLEASE! I WILL FAIL IF IT DOESNT GET DONE!

Anna35 [415]

In order to solve for this, we need to find the volumes of both the cylinder and cone described.

In order to find the area of the cylinder:
We use the equation V= $\pi r^{2} h$
So, V= $\pi 6^{2}16$
The volume of the cylinder is therefore approximately <span>1809.56 $m^{3}$

For the cone:
V= $\pi r^{2} \frac{h}{3}$
So, V= $\pi 6^{2} \frac{3}{3}$
Thus, the volume of the cone is 113.1 $m^{3}$

We add these volumes together to derive the solution, which is 1922.66 $m^{3}$ </span>