All categories

4 years ago

If LP = 15 and PR = 9, find LR. Explain.

Mathematics

2 answers:

Alla [95]4 years ago

6 0

Answer:

LR is 12

Step-by-step explanation:

LP is hypotenuse and PR is base so LR is perpendicular

formula to calculate perpendicular is

p^2=H^2 -b^2

p^2=15^2-9^2

p^2=225-81

p^2=144

p=12(root of 144 is 12)

sweet-ann [11.9K]4 years ago

4 0

Answer:

it would be 24 cuz 15 + 9 = 24

You might be interested in

How to solve f(x)=x2-8x+5

vfiekz [6]

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:

(

−

)

Focus:

(

−

)

Axis of Symmetry:

Directrix:

−

4 0

3 years ago

I need help pls pls pls

TEA [102]

Answer:

Mantle

Step-by-step explanation:

I think its mantle

6 0

3 years ago

|1|>-1<br> True or false

zmey [24]

Answer:

all work is pictured and shown

7 0

3 years ago

KTMN is a parallelogram . prove it .please help I need it by tomorrow no links please

Sav [38]

Answer:

This is a paralleogram because it machtes the defintion ofa four-sided plane rectilinear figure with opposite sides parallel.

Step-by-step explanation:

5 0

3 years ago

Help me out please?<br>chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

$=> \frac{5^3}{3^3} = \frac{125}{27}$

4 0

3 years ago

Read 2 more answers