Question

How can I find the area of a triangle with 3inches, 5inches, and 4inches?​

Answer 1

Given:

Sides of a triangle are

a = 3 in, b = 4 in and c = 5 in

To find:

The area of the triangle.

Solution:

Using Heron's formula:

$S=\frac{a+b+c}{2}$

$S=\frac{3+4+5}{2}$

S = 6 in

$A=\sqrt{s(s-a)(s-b)(s-c)}$

$A=\sqrt{6(6-3)(6-4)(6-5)}$

$A=\sqrt{6(3)(2)(1)}$

$A=\sqrt{36}$

$A=6$ in²

Area of a triangle is 6 in².

Answer 2

Given:

Given that the sides of the triangle are 3 inches, 5 inches and 4 inches.

We need to determine the area of the triangle.

Area of the triangle:

The area of triangle can be determined using the formula,

$A=\frac{1}{2}bh$

where b is the base of the triangle and h is the height of the triangle.

From the figure, it is obvious that the base of the triangle is 4 inches and the height of the triangle is 3 inches.

Substituting b = 4 and h = 3 in the above formula, we get;

$A=\frac{1}{2}(4)(3)$

$A=\frac{1}{2}(12)$

$A=6$

Thus, the area of the triangle is 6 square inches.