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iris [78.8K]
3 years ago
5

A larger number is five more than twice the smaller number their sum is 80 find the number

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

L= 5+2s

Step-by-step explanation:

Let L = the larger # and S = the smaller #.

A large # is 5 more than twice a smaller #.....This gives Eq 1) L = 5 + 2S

Their sum is 80...This gives Eq 2) L + S = 80.

Substitute Eq 1) into Eq 2), you get

L + S = 80

5 + 2S + S = 80

L = 5 + 2S

 

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Will mark brainliest for area.
Elena L [17]

Answer:

c

Step-by-step explanation:

first, find the area of the rectangle thing,

A = lw

14 x 8

112

but, there is a semicircle in it so you need to subtract that from it:

A = πr^2/2

A = π(4)^2/2

A = π16/2

A = 8π

A ≈ 25.132741228718346

then subtract that area from the area of the rectangle:

112 - 25.132741228718346

86.867258771281654

or about 89.9

6 0
3 years ago
The sum of two numbers is 72 the greater number is 8 more than the smaller number which equation can be used to solve for the sm
kobusy [5.1K]

Answer:

let x is the smaller number

bigger number is x + 8

The sum of two numbers is 72

so

x + (x+8) = 72

answer

x + (x + 8) = 72

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Who can help me?<br>please<br>Thank you​
4vir4ik [10]

The sum of the interior triangles in a triangle is 180, so if we add all the angle measures together, we should get 180. Therefore, we can make an equation like this,

110-2x+x+50+5x-40=180

Simplify this.

4x+120=180

4x=60

x=15

Now we can find each angle measure.

110-2x

110-2(15)

110-30

80

x+50

15+50

65

5x-40

5(15)-40

75-40

35

So the angle labeled 110-2x is the largest angle in the triangle.

7 0
3 years ago
Read 2 more answers
Find the distance from the origin to the graph of 7x+9y+11=0
Cerrena [4.2K]
One way to do it is with calculus. The distance between any point (x,y)=\left(x,-\dfrac{7x+11}9\right) on the line to the origin is given by

d(x)=\sqrt{x^2+\left(-\dfrac{7x+11}9\right)^2}=\dfrac{\sqrt{130x^2+154x+121}}9

Now, both d(x) and d(x)^2 attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

d(x)^2=\dfrac{130x^2+154x+121}{81}\implies\dfrac{\mathrm dd(x)^2}{\mathrm dx}=\dfrac{260}{81}x+\dfrac{154}{81}

Solving for (d(x)^2)'=0, you find a critical point of x=-\dfrac{77}{130}.

Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.

You have

\dfrac{\mathrm d^2d(x)^2}{\mathrm dx^2}=\dfrac{260}{81}>0

so indeed, a minimum occurs at x=-\dfrac{77}{130}.

The minimum distance is then

d\left(-\dfrac{77}{130}\right)=\dfrac{11}{\sqrt{130}}
4 0
3 years ago
Can someone explain why the answer is True. Will make brainliest.
MrRissso [65]

Answer:

True

Step-by-step explanation:

With Sin and Cos, the rule is that the opposites are the same:

SinA=CosB

CosB=SinA

In this problem, it is showing SinA=cosB, so it is the same, it is true.

Hope this helps!

8 0
3 years ago
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