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Nataliya [291]
3 years ago
6

Sin theata=3/5, then cos theata= ?

Mathematics
1 answer:
Elena-2011 [213]3 years ago
5 0

\bf sin(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a
\qquad
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{5^2-3^2}=a\implies \pm\sqrt{25-9}=a\implies \pm 4=a
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 4}}{\stackrel{hypotenuse}{5}}~\hfill

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