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nirvana33 [79]
3 years ago
13

What would the points be if y=2x-5 domain's are : -2, -1, 0, 1, 2,

Mathematics
1 answer:
cupoosta [38]3 years ago
4 0

Answer:

-9, -7, -5, -3, -1

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Find the area of an 11-gon with side length 5 inches.
Y_Kistochka [10]

Answer:

234.141

Step-by-step explanation:

The formula is \frac{11}{4}  *(s)^2*cot(\frac{\pi }{11}). If you substitute 5 in, you get \frac{275}{4} *cot(\pi /11) or 234.141

5 0
3 years ago
please help !!! A sphere and a cylinder have the same radius and height. The volume of the cylinder is 48cm^3 .
Kay [80]

Answer:

<u>The radius of the cylinder and sphere is 2.48 cm and the volume of the sphere is 64 cm³</u>

Step-by-step explanation:

Let's review the information given to us to answer the question correctly:

Volume of a cylinder = π * r² * h

π * r² * h = 48

r² * h = 48/3.1416

r² * h = 15.28

r = 2.48 cm, h = 2.48 cm

Now, we can calculate the volume of the sphere this way:

Volume of the sphere = 4/3 * π * r³

Volume of the sphere = 4/3 * π * 2.48³

Volume of the sphere = 4/3 * π * 15.28

Volume of the sphere = 1.33 * 3.1416 * 15.28

<u>Volume of the sphere = 64 cm³</u>

8 0
3 years ago
Read 2 more answers
Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?
Goshia [24]

Answer:

option C

A number line with a closed circle on  9 and shading to the left

Step-by-step explanation:

we have

2(x+1)\geq 20

solve for x

2x+2\geq 20

Subtract 2 both sides

2x+2-2\geq 20-2

2x\geq 18

Divide by 2 both sides

x\geq 9 --------> is equivalent to 9 \leq x

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to 9

A number line with a closed circle on  9 and shading to the right

3 0
3 years ago
Read 2 more answers
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
What are the answers?
madam [21]
Positive numbers is the last one
7 0
3 years ago
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