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s344n2d4d5 [400]
3 years ago
11

What is the shape of the following distribution? {9, 10, 10, 11, 11, 12, 12, 13, 13, 13, 14, 14, 14, 14, 15, 15, 15, 15, 16, 16,

16, 16, 17, 17, 17, 17, 18, 19, 20}
Mathematics
1 answer:
babunello [35]3 years ago
7 0
The shape of the distribution with the following data set you gave is skewed to the left or negatively skewed. This is because the frequency of each number increases as its value increases. 
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Explain how you can use multiplication to find the quotient 3/5 divided by 3/15. Then evaluate the expression
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when you divide 2 fractions, you reverse the second fraction then use multiplication


3/5 divided by 3/15 becomes

3/5 x 15/3 = 45/15 = 3

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Add positive 28 to get the sum 0
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Use the substitution method to sloved the systmem of equaions. Choose the correct order pair
vazorg [7]
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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
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Lana71 [14]

Answer:

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Step-by-step explanation:

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