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3 years ago

Can you please my math people

Mathematics

2 answers:

inessss [21]3 years ago

8 0

Answer:

(-3,0)

Step-by-step explanation:

graph the lines and look to see

valentina_108 [34]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

What is the value of B?

iragen [17]

$2x^2-12xy-32y^2=2(x-8y)(x+By)\qquad|\text{use distributive property}\\\\2x^2-12xy-32y^2=(2x-16y)(x+By)\\\\2x^2-12xy-32y^2=(2x)(x)+(2x)(By)+(-16y)(x)+(-16y)(By)\\\\2x^2-12xy-32y^2=2x^2+2Bxy-16xy-16By^2\\\\2x^2-12xy-32y^2=2x^2+(2B-16)xy+(-16By)$

$\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT$

<h3>Answer: B = 2</h3>

8 0

3 years ago

Can anyone help me figure out the answer to this

Alex17521 [72]

3x-11=17-4x add 4x to both sides

7x-11=17 add 11 to both sides

7x=28 divide both sides by 7

x=4

4 0

3 years ago

Part B

Georgia [21]

Answer:140

Step-by-step explanation: It is a really big number not the most reasonable answer for the low amount of marbles their are in the jar adding 58 and 82 gives you your answer

5 0

3 years ago

Keiko started an assignment at 5:28 PM and finished it at 6:52 PM.

Bumek [7]

Answer:

It took her 84 minutes (or 1 hour and 24 minutes) to finish.

5 0

3 years ago

Read 2 more answers

The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni

charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.

Mean pulse of sample 2 = 70 beats per minute.

(c)

The mean pulse rate of sample 1 underestimates the population mean.
The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

Perpectual Bempah 64
Megan Brooks 77
Jeff Honeycutt 89
Clarice Jefferson 69
Crystal Kurtenbach 89
Janette Lantka 65
Kevin McCarthy 88
Tammy Ohm 69
Kathy Wojdya 87

$\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44$

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

Janette: 65bpm
Clarice: 69bpm
Megan: 77bpm

Mean of Sample 1

$\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3$

Sample 2: {Janette,Clarice,Megan}

Perpetual: 64bpm
Clarice: 69bpm
Megan: 77bpm

Mean of Sample 2

$\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70$

The mean pulse of sample 1 is approximately 70.3 beats per minute.

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

The mean pulse rate of sample 1 underestimates the population mean.
The mean pulse rate of sample 2 underestimates the population mean.

7 0

3 years ago