Sin^{2} theta +cos theta = 2

1 answer:

4 0

$\bf sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\\\\
-------------------------------\\\\
\underline{sin^2(\theta )}+cos(\theta )=2\implies \underline{1-cos^2(\theta )}+cos(\theta )=2
\\\\\\
0=cos^2(\theta )-cos(\theta )+1$

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