Answer:
-x+6
Step-by-step explanation:
if f(x) = x^2-2x-24 and g(x) = x^2-x-30, find (f-g)(x).
Do to this, you have to subtract equation g from equation f.
If you write it down and subtract them, your x^2 will cancel out and you will be left with -2x - (-x) and -24 - (-30). This will leave you with -x +6
(-5,2) is located in the II quadrant because the x is negative and the y is positive.
(5,-5) is located in the IV quadrant because the x is positive and the y is negative.
(2,-5) is also located in the IV quadrant because the x is positive and the y is negative.
(-4,-5) is located in the III quadrant because both x and y are negative.
I only know the answer for b I don't know the answer for d. So here is the answer for b 9 time 9= to 18+11+8x4-1=60
Answer:
4s
Step-by-step explanation:
You can just pretend it's like normal addition and subtraction but with s, so you do -2s - 4s + 10s = -6s + 10s = 4s.
Answer:
1 
or
Step-by-step explanation:
