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TEA [102]
3 years ago
15

Jordan has a garden that is enclosed by a rectangular fence. The perimeter of the garden is 84 feet. The length of one side of f

encing is 8 yards. What is the area of Jordan's garden?
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0

Answer:

504 ft

Step-by-step explanation:

Perimeter = 2(width) + 2(length)

Convert yards to feet

1yard=3feet

8yards=?

8*3/1 = 24feet

84 = 2(w) + 2(24)

84 = 2w + 42

84 - 42 = 2w

42 = 2w

w = 21

Area = 1 * w

        = 21 * 24

        = 504 ft

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ELEN [110]

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

3x+y=8 (1)

2x+2y=8 (2)

Let's multiply the first equation by 2 and subtract it to the second equation  

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Using this value in (1) we can find y.

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Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

3 0
3 years ago
tammy is 14 years old. she has a younger sister and an older brother. her sister is 12. the mean of all their ages is 14. how ol
mafiozo [28]

Answer:

16

Step-by-step explanation:

To solve, we can use an equation finding the average of the siblings'ages.

\frac{14 + 12 + x}{3}  = 14 \\  \ 14 + 12 + x = 42 \\ x = 42 - 14 - 12 \\ x = 16

7 0
3 years ago
15 points PLEASE ANSWER
Xelga [282]

Answer:

D. (25π - 50) sq m

Step-by-step explanation:

Since ABCD is a square with the area of 100, we know that the dimensions are 10 by 10. With that, we can find that triangle ABC = 50 sq m because of (h*l)/2. Since A is the center of the circle that contains arc BD, we know that 10 is the radius of the quarter-circle ABC. Using (πr^2)/4 to get the area of the quarter-circle, we get that the quarter-circle ABC = 25π sq m. But the original triangle ABC in the quarter-circle is not shaded. Therefore, we subtract 50 from 25π, which leads to (25π - 50) sq m.

I hope this helped! :D

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3 years ago
PLSS HELPP ITS DO IN A FEW MINUTES
PSYCHO15rus [73]

Answer:

10%.

Step-by-step explanation:

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3 years ago
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Ket [755]
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4 years ago
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