The answer would be 4 and 2 over 3
I think the answer would be -3
Answer:
We have to choose 21 strings to be sure we have chosen at least 6 strings of the same type.
Step-by-step explanation:
Since the string type is determined by the initial and terminal bits as understood from the question, then the value of the bits between the initial and terminal bits is of no concern to us.
Now, to be sure you have atleast 6 of the same type, we select each string five times. By doing this, we have already selected 20 strings because we have 4 strings there. Now if you choose any of the string one more time, we are certain that we must have chosen atleast 6 strings that are the same. This means we have to choose 21 strings to be sure we have chosen at least 6 strings of the same type.
<u>Answer:
</u>
Required value of f(0) = 2 and common ratio of given geometric sequence is 6.
<u>Solution:
</u>
Given sequence rule for geometric sequence is f(x) = f(x-1) multiplied by 6 that is,
f(x) =6(f(x-1)) .
Also given that f(1) = 12 .
We need to determine f(0) and common ratio.
Calculating f(0)
:
On substituting x = 1 in given sequence rule, we get
f(1) = 6(f(1-1))
f(1) = 6(f(0))
f(0) =
Given that f(1) = 12, substituting in above expression we get
so f(0) =
= 2
Calculation common ratio:
On substituting x = 2 in given sequence rule, we get
f(2) = 6(f(2-1))
f(2) = 6(f(1))
= 6
And
is nothing but common ratio.
Hence required value of f(0) = 2 and common ratio of given geometric sequence is 6.