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ra1l [238]
3 years ago
15

What is the equation of a line that contains the point (4, 0) and is parallel to x + y = 2?

Mathematics
1 answer:
gogolik [260]3 years ago
6 0

Answer:

x + y = 4 or y = -x + 4

Step-by-step explanation:

0 = -1[4] + b

4 = b

y = -x + 4

If you want it in <em>Standard</em><em> </em><em>Form</em>:

y = -x + 4

+x +x

_________

x + y = 4 >> Line in Standard Form

* Since the <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] is -1 and that parallel lines have SIMILAR SLOPES, -1 remains the same.

I am joyous to assist you anytime.

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What is an equation of the line that passes through the points (-6, -2) and
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Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

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Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

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Finding y-intercept

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So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

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