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Mathematics

1 answer:

marta [7]2 years ago

8 0

Answer:

Whats the question

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What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o

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The given geometric series is

$\sum_{n = 1}^{ \infty} 12( { - \frac{1}{9} })^{n - 1}$

We want to determine the first term of this geometric series.

Recall that the explicit formula is

$a_{n} = 12( { - \frac{1}{9} })^{n - 1}$

To find the first term, we put n=1 to get:

$a_{1} = 12( { - \frac{1}{9} })^{1 - 1}$

This gives us:

$a_{1} = 12( { - \frac{1}{9} })^{0}$

$a_{1} = 12(1) = 12$

Therefore the first term is 12

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