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2 years ago

Given the following sets. A = {0, 1, 2, 3) B = (a, b, c, d] C = {0, a, 2, b) Find BC

Mathematics

1 answer:

k0ka [10]2 years ago

7 0

Answer:

C={0, a, 2, b, 4, c,}

Step-by-step explanation:

I thing you are doing patterns but I hope this helps

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Identify the constant term in this expression.

tatuchka [14]

Answer:answer is 2y

Step-by-step explanation:

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3 years ago

Would you measure the length of a jump rope in inches or in feet? explain your choice

yan [13]

Depending on the length of the jump rope but usually you may need both feet and inches. By checking the average lengths of a jump rope you have: 7ft, 8ft,9ft,10ft for different heights so from this information the correct answer is feet

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3 years ago

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A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be use

Tamiku [17]

75-3×3x=?
I believe that would be the equation.

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3 years ago

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Factor. 3x(y−4)−2(y−4) Enter your answer in the box.

NISA [10]

Answer: Use the distributive property to multiply 3 by y−4.

3y−12−2(y−4)

Use the distributive property to multiply −2 by y−4.

3y−12−2y+8

Combine 3y and −2y to get y.

y−12+8

Add −12 and 8 to get −4.

Anwser:

y−4

Step-by-step explanation:

Hope this helps!

6 0

2 years ago

If a student randomly guesses at 20 multiple-choice questions, find the probability that the student gets exactly four correct.

ad-work [718]

Answer:

Probability = 0.190

Step-by-step explanation:

Given:

Number of questions, 'n' = 20

Each question has four choices.

Let event of choosing correct answer be success and its probability be represented by 'p'.

Therefore, event of choosing wrong answer is failure and its probability be represented by 'q'.

Now, probability of success is choosing one correct answer out of 4 options. So, $p=\frac{1}{4}=0.25$

Now, 'p' and 'q' are complements of each other. Therefore,

$q=1-p=1-0.25=0.75$

Now, we need 4 successes. Therefore, $x=4$

Using Bernoulli's theorem to find 'x' successes from 'n' questions, we get:

$P(x)=_{x}^{n}\textrm{C}p^xq^{n-x}$

Plug in 4 for 'x', 20 for 'n', 0.25 for 'p' and 0.75 for 'q'. Solve.

$P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{20-4}\\P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{16}\\P(4)=4845\times (0.25)^4\times (0.65)^{16}\\\\P(4)=0.1896\approx0.190$

Therefore, the probability of getting 4 correct answers out of 20 questions is 0.190.

6 0

2 years ago