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3 years ago

6

Please help me find the remainders

1 answer:

Bingel [31]3 years ago

4 0

Answer:

- 2 and 7

Step-by-step explanation:

A polynomial P(x) divided by (x + h) has remainder f(- h) ← remainder theorem

P(x) divided by (x + 5) has remainder P(- 5) = - 2 ( from result given )

P(x) divided by (x - 3) has remainder P(3) = 7 ( from result given )

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PLEASE HELP! Let f(x)= 6x+1 find f(a) + f(2)

SpyIntel [72]

Answer:

6(a)+14

Step-by-step explanation:

First you need to find f(a) and f(2) separately, then add them together after

f(a) = 6(a)+1

f(2) = 6(2)+1 = 12+1 = 13

so f(a)+f(2) = 6(a)+1+13 = 6(a)+14

6 0

3 years ago

use the slope formula to determine the slope of a line that passes through the points (4,9) and (-8,-6)

larisa86 [58]

$\frac{-6-9}{-8-4}\\ \\\frac{-15}{-12}\\ \\= \frac{5}{4}$

Slope: 5/4

6 0

3 years ago

Make up your own problem and solve it

Gennadij [26K]

Answer:

= $ (x + 145 + 145)

= $ (x + 290)

So in this way end of every week her salary will increase by $ 145.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)

oksano4ka [1.4K]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9$

6 0

3 years ago

Can someone please help me??

dmitriy555 [2]

Answer:

I is clear that, the linear equation $5x+12=5x-7$ has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

$\frac{2}{3}\left(9x+6\right)=6x+4$

$6x+4=6x+4$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$6x+4-4=6x+4-4$

$6x=6x$

$\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}$

$6x-6x=6x-6x$

$0=0$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

<u>Checking the 2nd option:</u>

$5x+12=5x-7$

$\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}$

$5x+12-5x=5x-7-5x$

$\mathrm{Simplify}$

$12=-7$

$\mathrm{The\:sides\:are\:not\:equal}$

$\mathrm{No\:Solution}$

<u>Checking the 3rd option:</u>

$4x+7=3x+7$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}$

$4x+7-7=3x+7-7$

$\mathrm{Simplify}$

$4x=3x$

$\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}$

$4x-3x=3x-3x$

$\mathrm{Simplify}$

$x=0$

<u>Checking the 4th option:</u>

$-3\left(2x-5\right)=15-6x$

$\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}$

$-6x+15-15=15-6x-15$

$\mathrm{Simplify}\$

$-6x=-6x$

$\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}$

$-6x+6x=-6x+6x$

$\mathrm{Simplify}$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

Result:

Therefore, from the above calculations it is clear that, the linear equation

$5x+12=5x-7$ has no solution.

4 0

3 years ago