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zimovet [89]
3 years ago
5

Maria ate 1/3of a pie.Her sister,rebecca,ate 1/5of that.what fraction of the whole pie did rebecca eat?

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer: the fraction of the whole pie that Rebecca ate is 1/15

Step-by-step explanation:

Let x represent the size or area of the whole pie. Maria ate 1/3 of the pie. This means that the amount of pie that maria ate is 1/3 × x = x/3

Her sister,Rebecca ate 1/5 of that. This means that Rebecca ate 1/5 of the amount that Maria ate. The amount that Rebecca ate will be expressed as 1/5 × x/3 = x/15

To determine the fraction of the whole pie that Rebecca ate, we will divide the amount that Rebecca ate by the size of the whole pie. It becomes

x/15/x = x/15 × 1/x

= 1/15

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Equivalent radios to 2:12
natali 33 [55]

Answer:

<h2>1:6</h2>

Step-by-step explanation:

2:12

Cross cancel common factor : 2

2 \div 2 = 1 \\ 12 \div 2 = 6 \\ 1:6

8 0
3 years ago
Help please with explain so for further questions like this
Yakvenalex [24]
Rmember (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)this is just alot of busy work

find f+g first then find f-g


f+g=(x-4)/(x+9)+(x-9)/(x+4)
make denomenator the same
multiply left one by (x+4)/(x+4) and right one by (x+9)/(x+9)
[(x-4)(x+4)]/[(x+9)(x+4)]+[(x-9)(x+9)]/[(x+9)(x+4)]
[x²-16]/[(x+9)(x+4)]+[x²-81]/[(x+9)(x+4)]
[x²+x²-16-81]/[(x+9)(x+4)]
[2x²-97]/[(x+9)(x+4)]

now f-g
[x²-16]/[(x+9)(x+4)]-[x²-81]/[(x+9)(x+4)]
[x²-x²-16+81]/[(x+9)(x+4)]
[65]/[(x+9)(x+4)]


now we got
\frac{ \frac{2x^2-97}{(x+9)(x+4)} }{ \frac{65}{(x+9)(x+4)} }
invert and multiply
(\frac{2x^2-97}{(x+9)(x+4)})(\frac{(x+9)(x+4)}{65})
\frac{2x^2-97}{65}

2nd option
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3 years ago
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Igoryamba
The answer to the question is 114
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Please need help explanation need it
nydimaria [60]

Answer:

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Step-by-step explanation:

The volume is given by

V = l*w*h  where l is the length , w is the width and h is the height

V = 7*4*11

V = 308 m^3

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