Answer:
two solutions : (-3;4) and (-5;6)
Step-by-step explanation:
hello :
X²+y²+18x+29=0 ..(1)
X+y=1 ...(2)
by (2) : y = 1 - x
put this value in (1) : x² +(1-x)² +18x+29 = 0
x² +1 +x² -2x+18x +29 =0
2x²+16x +30 = 0
x²+8x+15 =0
delta = b²-4ac a=1 b=8 c = 15
delta = (8)²-4(1)(15)=64-60 =4 = 2²
X1=(-8+2)/2 = - 3
X2=(-8-2)/2 = - 5
case 1 : x = -3 y = 1 - (-3) = 4
case 2 : x = -5 y = 1 - (-5) = 6
Answer:
Both Scott and Tara have responded correctly.
Step-by-step explanation:
we know that
The area of a trapezoid is equal to
A=(1/2)[b1+b2]h
we have
b1=16 cm
b2=24 cm
h=8 cm -----> <em>Note</em> The height is 8 cm instead of 18 cm
substitute
A=(1/2)[16+24](8)
A=160 cm²
<em>Verify Scott 's work</em>
<em>Note</em> Scott wrote A = (1/2)(24 + 16)(8) instead of A = 2(24 + 16)(8)
Remember that the Commutative Property establishes "The order of the addends does not alter its result"
so
(24+16)=(16+24)
A = (1/2)(24 + 16)(8)=160 cm²
<em>Verify Tara's work</em>
<em>Note</em> Tara wrote A = (1/2)(16+24)(8) instead of A = (16 + 24)(8)
A = (1/2)(16+24)(8)=160 cm²
For this questions you need to memorize formula of triangle area. for question 5, just substitute the value into the formula. for Q6 you need to use pythagorean theorem formula to find the lenght of each triangle that i already seperated
Answer:
22
Step-by-step explanation:
brainliest?
Answer:
V≈184.31
Step-by-step explanation:
V=πr2h
3=π·42·11
3≈184.30677
