The following spectroscopic data corresponds to an an unknown compound with the molecular formula C4H8O2. Deduce and draw the st
ructure of the compound that corresponds to the data. 1H NMR: δ 4.07 (quartet, 2H), 1.97 (singlet, 3H), 1.18 (triplet, 3H) ppm. 13C NMR: δ 170, 60, 20, 14 ppm.
1 answer:
Answer:
The name of the structure is ethyl acetate with one double bond. The attached document contains the structure of the compound
Step-by-step explanation:
¹H NMR =δ4.07(quartet), 1.97( singlet), 1.18(triplet)
2H 3H 3H
¹³C NMR = δ 170, 60, 20, 10 ppm
from the molecular formula,C₄H₈O₂ and spectrum study, the structure of the compound will have a double bond which is calculated as DU= 4+1-(8/2)= 1
thus, the name of the compound as drawn in the attachment is ethyl acetate
You might be interested in
Answer: For 10 sessions, the cost of the two plans the same.
Step-by-step explanation:
Let x= Number of sessions.
Given: Christian’s Gym charges a one-time fee of $50 plus $30 per session for a personal trainer.
Total charge for x sessions = 50+30x
Nicole's fitness center charges a yearly fee of $250 plus $10 for each session with a trainer.
Total charge for x sessions = 250+10x
When both plan charges the same, then
i.e. For 10 sessions, the cost of the two plans the same.