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3 years ago

Put the following equation of a line into slope-intercept form, simplifying all fractions. y - 3x = -1

Mathematics

2 answers:

Archy [21]3 years ago

7 0

Answer:

y=3x-1

Step-by-step explanation:

y-3x=-1

y-3x+3x=-1+3x

y=3x-1

mestny [16]3 years ago

7 0

Answer:

y=3x-1

Step-by-step explanation:

y-3x=-1

y=3x+(-1)

y=3x-1

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(24) x j - 16

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4 years ago

Identify the following pairs of angles as complementary, supplementary, adjacent, and/or vertical angles.

Anna [14]

Answer:

ABH and HBC ---- Complementary angles ( Sum of complementary anfges = 90 degrees )

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4 years ago

Given AG bisects CD, IJ bisects CE, and BH bisects ED. Prove KE = FD.

OverLord2011 [107]

When a line is bisected, the line is divided into equal halves.

See below for the proof of $\mathbf{KE \cong FD}$

The given parameters are:

AC bisects CD
IJ bisects CE
BH bisects ED

By definition of segment bisection, we have:

$\mathbf{CK \cong KE}$
$\mathbf{EF \cong FD}$
$\mathbf{CE \cong ED}$

By definition of congruent segments, the above congruence equations become:

$\mathbf{CK = KE}$
$\mathbf{EF = FD}$
$\mathbf{CE = ED}$

By segment addition postulate, we have:

$\mathbf{CE = CK + KE}$
$\mathbf{ED = EF + FD}$

Substitute $\mathbf{ED = EF + FD}$ in $\mathbf{CE = ED}$

$\mathbf{CK + KE = EF + FD}$

Substitute $\mathbf{CK = KE}$ and $\mathbf{EF = FD}$

$\mathbf{KE + KE = FD + FD}$

Simplify

$\mathbf{2KE = 2FD}$

Apply division property of equality

$\mathbf{KE = FD}$

By definition of congruent segments

$\mathbf{KE \cong FD}$

Read more about proofs of congruent segments at:

brainly.com/question/11494126

6 0

3 years ago

For points What is 10+18=

ivanzaharov [21]

Answer:

Answer is 28.

Step-by-step explanation:

and thanks for free points.

6 0

3 years ago

Read 2 more answers

Put the following equation of a line into slope-intercept form, simplifying all fractions. y - 3x = -1​

Put the following equation of a line into slope-intercept form, simplifying all fractions. y - 3x = -1