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Tamiku [17]
3 years ago
9

A student worked out an equation and below is his solution. is the answer correct? If not, where was the error and what is the c

orrect answer?
-4(6-r)=12
-24-4R=12
-4R=36
R=-9
Mathematics
1 answer:
Lelu [443]3 years ago
4 0

Answer:

His answer is wrong.

Step-by-step explanation:

-4(6-R)=12  <-- Since R is negative, -4 times -R results in a positive so, 4R.

-24+4R=12

+24       +24

--------------------

4R = 36

R= 9

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A city has 3 new houses for every 9 old houses. If there are 21 new houses in the city, how many old houses are there?
kipiarov [429]
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.
5 0
3 years ago
In B E C, F is the centroid, and AC = 12. Find A F and F C
klemol [59]

bearing in mind that the centroid in a triangle cuts each of the three medians in a 2:1 ratio.

since we know that A C = 12, let's split it in a 2:1 ratio then, cleary from the picture the larger is F C, so F C : A F is on a 2:1 ratio.

\bf A C=A F+F C\qquad \qquad \cfrac{F C}{A F}=\cfrac{2}{1}\qquad \qquad \cfrac{2\cdot \frac{12}{2+1}}{1\cdot \frac{12}{2+1}}\implies \cfrac{2\cdot 4}{1\cdot 4}\implies \cfrac{8}{4}

4 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
A researcher is conducting a study of charitable donations by surveying a simple random sample of households in a certain city.
nirvana33 [79]

Answer:

H0: p ≤ 0.50

Ha: p > 0.50

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

Let p represent the proportion of households in the city that gave a charitable donation in the past year

The null hypothesis is that the proportion of households in the city that gave a charitable donation in the past year is not more that 0.50

H0: p ≤ 0.50

The alternative hypothesis is that the proportion of households in the city that gave a charitable donation in the past year is more that 0.50

Ha: p > 0.50

7 0
3 years ago
Please help answer this question for me.
Lilit [14]

Answer:

Yes

Step-by-step explanation:

4 0
3 years ago
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