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3 years ago

The expression 20x + 30 represents the area of the figure below. Use distributive property to find the dimensions.

Mathematics

1 answer:

Delvig [45]3 years ago

4 0

Answer:

i am sorry it i knew it but i can remember it hope you have a great day.

Step-by-step explanation:

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HELP ME ! beautiful people that are good at math

ANTONII [103]

-3(-4y+3) +7y
Expand
12y-9+7y
Add like terms
19y-9

8 0

3 years ago

The mean of five numbers is 8. when another number is added the mean is 7. find the number added

sasho [114]

Answer:

$\large \boxed{\sf \ \ 2 \ \ }$

Step-by-step explanation:

Hello,

<u>The mean of five numbers is 8</u> so we can write

$\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8$

<u>When another number is added the mean is 7</u>, let s note x the another number we can write

$\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7$

From the first equation we can say

$x_1+x_2+x_3+x_4+x_5=8*5=40$

So the second equation becomes

$\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\ \dfrac{40+x}{6}=7\\\\40 + x = 6*7=42\\\\ x = 42-40 = 2\\$

The solution is then 2

Hope this helps

4 0

3 years ago

there are a 160 boys and girls playing in the soccer tournament 32 of the students are wearing orange what percentage of the pla

madreJ [45]

Answer:

the ansrew is 3%

Step-by-step explanation:

160 divided by 32= 3% mostly around 3.3125 i am not 100% sure so u should probably wait for someone else but this is my way of seeing the problem.

3 0

3 years ago

Read 2 more answers

Suppose William and Donald both drive the same car, and have the same

nataly862011 [7]

Answer: William

Step-by-step explanation: This is true because whichever has a better gas mileage pays less, so the bigger number per year has better mileage, so 15,000 would have better which is Donald, and William has 12,000 which is worse, so he would have to pay more.

5 0

4 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago