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3 years ago

Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x).

Mathematics

1 answer:

scZoUnD [109]3 years ago

5 0

<h3>Answer: 2x^2 + 6x - 4</h3>

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Work Shown:

f(x) - g(x) = [ f(x) ] - [ g(x) ]

f(x) - g(x) = ( 3x^2+x-3) - ( x^2-5x+1 )

f(x) - g(x) = 3x^2+x-3 - x^2+5x-1

f(x) - g(x) = (3x^2-x^2) + (x+5x) + (-3-1)

f(x) - g(x) = 2x^2 + 6x - 4

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A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.

Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}$

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}$

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2 years ago

Y=x-5; domain = {4,6,8}

Lostsunrise [7]

Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

<u><em>The question asks for the range.</em></u>

The function given is

$y=x-5$

The domain is the set of 3 numbers:

Domain = {4,6,8}

We need to find the range.

First, the range is the set of all y-values for which the function is defined.

When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.

So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

$y=x-5\\y=4-5\\y=-1$

At x = 6:

$y=x-5\\y=6-5\\y=1$

At x = 8:

$y=x-5\\y=8-5\\y=3$

Thus, the range is:

Range = {-1, 1, 3}

7 0

3 years ago