Answer:
I hope it helps . For any clarification , Please notify me through the comment section .
Step-by-step explanation:
![f(x) = 3x-5\\g(x) = 2(x-1)\\ \\g(-3) = 2(-3-1)\\g(-3) = 2(-4)\\g(-3) = -8\\\\f[g(x)] = f(2(x-1)\\f[g(x)] = 3[2(x-1)]-5\\f[g(x)] = 3[2x-2]-5\\f[g(x)] = 6x-6-5\\f[g(x)] = 6x-11\\\\g[f(x)] = g[3x-5]\\g[f(x)] = 2[3x-5-1]\\g[f(x)] = 6x -10-2\\g[f(x)] = 6x -12](https://tex.z-dn.net/?f=f%28x%29%20%3D%203x-5%5C%5Cg%28x%29%20%3D%202%28x-1%29%5C%5C%20%5C%5Cg%28-3%29%20%3D%202%28-3-1%29%5C%5Cg%28-3%29%20%3D%202%28-4%29%5C%5Cg%28-3%29%20%3D%20-8%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%20f%282%28x-1%29%5C%5Cf%5Bg%28x%29%5D%20%3D%203%5B2%28x-1%29%5D-5%5C%5Cf%5Bg%28x%29%5D%20%3D%203%5B2x-2%5D-5%5C%5Cf%5Bg%28x%29%5D%20%3D%206x-6-5%5C%5Cf%5Bg%28x%29%5D%20%3D%206x-11%5C%5C%5C%5Cg%5Bf%28x%29%5D%20%3D%20g%5B3x-5%5D%5C%5Cg%5Bf%28x%29%5D%20%20%3D%202%5B3x-5-1%5D%5C%5Cg%5Bf%28x%29%5D%20%3D%206x%20-10-2%5C%5Cg%5Bf%28x%29%5D%20%20%3D%206x%20-12)
It is the last one.
A pre-image is the original before another shape is created from it, either dilated, translated, reflected, or rotated.
5.46 ÷ 3 = 1.82
1.82 x 5 = 9.1
The answer is "9.10"
The variables aren't the same so no they are not alike