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il63 [147K]
4 years ago
8

Which model is most appropriate for the data shown in the graph below?

Mathematics
2 answers:
Fantom [35]4 years ago
4 0
Quadratic is like a parabola.
Linear is a straight line.
Exponential is like half of a parabola, but increases much faster.
A line is a line.
tangare [24]4 years ago
3 0

Answer:

The correct option is c.

Step-by-step explanation:

In a quadratic function, for more that one inputs there exist same output.

The rate of change of a line and linear  function is constant.

Conditions of an exponential function:

1. The rate of change of a exponential function is not constant. The exponential function increase or decrease gradually.

2. Domain of an exponential function is all real numbers.

3. For one input there exist a unique output.

From the given graph it is clear that the function is increasing at increasing rate. The given graph satisfy all the conditions of an exponential function, so the given graph represents an exponential function.

An exponential function is defined as

f(x)=ab^x

The graph passing through the points (1,1) and (2,3).

1=ab^1                     ..... (1)

3=ab^2                     ..... (2)

On solving (1) and (2), we get

a=\frac{1}{3},b=3

f(x)=\frac{1}{3}(3)^x

Therefore the correct option is c.

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Please help me! It would be amazing if you can!
jasenka [17]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
If (x+ 1) is a factor of the polynomial x³ + px² + x + 6 = 0. Find p.​
irakobra [83]

Answer:

p=4

Step-by-step explanation:

plug x=-1 into the polynomial with the unknown

(-1)³+p(-1)+(-1)+6=0

-1-p-1+6=0

-p+4=0

p=4

4 0
2 years ago
A farmer harvests 850kg of parsnips. 30% go to the local market and 50% go to a local supermarket. What mass of parsnips are lef
olga nikolaevna [1]

answer is 170

---------------------------

50% of 850 = 425

30% of 850 = 255

425 + 255 = 680

850 - 680 = 170

6 0
3 years ago
in the given figure, AB//PQ//CD. AB = x units. CD = y units and PQ = z unites. Prove that 1/x + 1/y = 1/z
Arlecino [84]
12. ∆ABD is similar to ∆PQD, so
   QD/z = BD/x
Likewise ∆CDB is similar to ∆PQB, so
   QB/z = BD/y

Since QD + QB = BD, you have
   QD/z + QB/z = BD/x + BD/y
   BD/z = BD/x + BD/y
Dividing by BD gives the desired result:
   1/x + 1/y = 1/z


13. Triangles ABD, BCD, and ACB are all similar. This means
   AB/AC = AD/AB
   AB² = AC×AD = (4 cm)×(9 cm)
   AB² = 36 cm²
   AB = 6 cm
and
   BD/CD = AD/BD
   BD² = CD×AD = (5 cm)×(4 cm)
   BD² = 20 cm²
   BD = 2√5 cm
7 0
3 years ago
For an account that earns interest compounded annually, find the balance of the account. Round your answer to the nearest cent.(
agasfer [191]
You can simply use S.I=PRT/100 as P stands for principal,R stands for rate and T stands for time.Hope dis helps
7 0
3 years ago
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