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Evgen [1.6K]
3 years ago
7

3(7x+9)=21-1 classify the equation as having the one solution or infinitely many

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0
X= -1/3 or as an alternative form x=-0.3 and x=-3 exponent minus 1
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Dan's goal is to raise more than $4000.00 in order to buy a car his senior year. If he has $2150 saved already and has a job tha
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185

Step-by-step explanation:

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3 years ago
The graph of y=ax^2+bx+c passes through points (0,5), (1,10), and (2,19). Find a+b+c.
nataly862011 [7]

Answer:   a = 2   b = 3   c = 5  

Literally a+ b+c = 10, but I don't think that's what the question means to ask.

the equation is 2x² +3x + 5

Step-by-step explanation:   Substitute the values of the given coordinates into the formula and use algebra (solve a system of equations by substitution and elimination) to get the values  of a,b & c

y=ax²+bx+c    using  (0,5), (1,10), and (2,19)

5=a(0)²+b(0)+c   becomes 5= 0+0 + c .so we find c = 5

10=a(1)²+b(1)+c    becomes 10 = a + b + c

19=a(2)²+b(2)+c .  becomes 19 = 4a + 2b + c

Substitute the 5 for c.  Then rewrite

10 = a + b + 5      becomes     5 = a+ b     to eliminate b multiply this be (-2)

(-2)( 5 = a+ b) .to get -10 = -2a - 2b  

19 = 4a + 2b + 5  becomes   14 = 4a + 2b  

_______________  Add these two

14 = 4a + 2b

<u>-10 = -2a - 2b</u><u> </u>    this will eliminate the "b" term

4 = 2a       divide both sides by 2   so you have   a = 2  

substitute in 10=a(1)²+b(1)+5 to find b

10=2(1)²+b(1)+5 .becomes  5 = 2 + b   Subtract 2 from both sides

b = 3

So now you have all three values:  

a = 2  b= 3  c = 5  

I am attaching the graph. I hope this deserves Brainiest.

Best wishes in your studies!

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3 years ago
PLEASE HELP!!! Isabell needs to memorize words on a vocabulary list for Spanish class. She has memorize 12 of the words, which
valina [46]

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Step-by-step explanation:

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4 x 4 = 16

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3 years ago
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Which statement describes a unit rate?
Artyom0805 [142]

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C

Step-by-step explanation:

Because it is saying he drove 45 miles per hour.

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3 years ago
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#8 please. GCF of 117, 99, and 126
Advocard [28]
The factors of 117 are: 1, 3, 9, 13, 39, and 117
The factors of 99 are: 1, 3, 9, 11, 33, and 99 
The factors of 126 are: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126

The greatest common factors of 117, 99, and 126 are: 1, 3, and 9. And according to your answer choices your answer is C. 9
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3 years ago
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