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lapo4ka [179]
3 years ago
8

4/9 converted into a decimal rounded to the nearest thousand

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0
0.444 is the answer to the question
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Write a equation of a hyperbola given the foci and the asymptotes
professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

a=3,\text{ and b=4}

To evaluate the value of h and k,

undefined

3 0
1 year ago
Find the missing angle measure A=51°, B=82°, C=5x+2
Shalnov [3]

I'm assuming you mean triangle angles?
If so, all angles add up to 180 so combine them and set them equal to 180.
51+82+5x+2=180
135+5x=180
5x=45
x=9

8 0
3 years ago
What is the greatest common factor of 7ab and 8b^3
Vlad [161]

Answer:

b

Step-by-step explanation:

The greatest common factor is the largest value two numbers share in common which multiplies to each of the numbers.

7ab has factors 7, a, b

8b^3 has factors 2, 4, 8, b, b, b

These share in common b.

3 0
3 years ago
Find the equation of a line that is perpendicular to x+y=8 and passes through the point (8, 10).
ArbitrLikvidat [17]

Answer:

Y = -x + 2

Step-by-step explanation:

y = -x + 8

y = 1x + b

10 = 8 + b

b = 2

6 0
3 years ago
Read 2 more answers
Help
Lubov Fominskaja [6]

Answer:

x=5

Step-by-step explanation:

(8x-8)3/2=64

(24x-8)/2=64 -You are distributing the three

12x-4=64 -You divide the whole thing by two

12x=60 -You subtract the four from both sides

x=5 - You divided the twelve from both sides

Hope this helps!

7 0
3 years ago
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