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san4es73 [151]
4 years ago
9

I’m confused. What are the true ones?

Mathematics
2 answers:
Aleks [24]4 years ago
7 0
A & C

A function can be determined by the simple verticale line test: if you were to draw a verticale line through the data and it passes through more than one point of it, it is not a function. Since a verticale line in this situation would pass through the whole of the data, it is NOT a function, so that rules out B, D, and E. A is correct, because the equation of the line is x=3.
Valentin [98]4 years ago
5 0

Answer:

The true statements are option A and option C

Step-by-step explanation:

The equation of the line is x= 3

A relation between two sets is said to be a function only when each and every element of the first set have one and only unique image in the second set.

But since the x= 3 have more than one y -value , it is not a function.

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Please help with khan
kodGreya [7K]

Answer:

not 100% but I think it's Step 1

3 0
2 years ago
Which equation represents a proportional situation?
ad-work [718]
The answer is a and the it do not have y intercept
3 0
3 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%
zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

p = 0.2*0.25 = 0.05

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

0.05 + 0.05*0.8 + 0.75*0.2 = 0.24

24% of the employees will suffer at least one lost-time accident over the two-year period

3 0
3 years ago
Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student
AysviL [449]

Answer:

The mean calculated for this case is \bar X=584

And the 95% confidence interval is given by:

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=584

The sample deviation calculated s=86.776

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

3 0
3 years ago
Simplify 16-3(8-3)2÷5
GenaCL600 [577]

Answer:

10/1 = 10

Step-by-step explanation:

1) Subtract: 8 - 3 = 5

2) Multiple: 3 * the result of step No. 1 = 3 * 5 = 15

3) Multiple: the result of step No. 2 * 2 = 15 * 2 = 30

4) Divide: the result of step No. 3 : 5 = 30 : 5 = 6

5) Subtract: 16 - the result of step No. 4 = 16 - 6 = 10

3 0
3 years ago
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